(5+i)^2/3-1

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Solution for (5+i)^2/3-1 equation: 


i in (-oo:+oo)

((i+5)^2)/3-1 = 0

((i+5)^2)/3+(-1*3)/3 = 0

(i+5)^2-1*3 = 0

i^2+10*i+22 = 0

i^2+10*i+22 = 0

i^2+10*i+22 = 0

DELTA = 10^2-(1*4*22)

DELTA = 12

DELTA > 0

i = (12^(1/2)-10)/(1*2) or i = (-12^(1/2)-10)/(1*2)

i = (2*3^(1/2)-10)/2 or i = (-2*3^(1/2)-10)/2

(i-((-2*3^(1/2)-10)/2))*(i-((2*3^(1/2)-10)/2)) = 0

((i-((-2*3^(1/2)-10)/2))*(i-((2*3^(1/2)-10)/2)))/3 = 0

((i-((-2*3^(1/2)-10)/2))*(i-((2*3^(1/2)-10)/2)))/3 = 0 // * 3

(i-((-2*3^(1/2)-10)/2))*(i-((2*3^(1/2)-10)/2)) = 0

( i-((-2*3^(1/2)-10)/2) )

i-((-2*3^(1/2)-10)/2) = 0 // + (-2*3^(1/2)-10)/2

i = (-2*3^(1/2)-10)/2

( i-((2*3^(1/2)-10)/2) )

i-((2*3^(1/2)-10)/2) = 0 // + (2*3^(1/2)-10)/2

i = (2*3^(1/2)-10)/2

i in { (-2*3^(1/2)-10)/2, (2*3^(1/2)-10)/2 }

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